document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=10631>Question 10631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The gym is 21 years older than the auditorium.  The gym is also 3 times as old as the auditorium.  How old is each building? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5633 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5633\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let G = age of gym and A = age of auditorium.\r<BR>\n" );
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document.write( "G = A + 21 yrs.  The gym is 21 years older than the auditorium.<BR>\n" );
document.write( "G = 3A The gym is 3 times as old as the auditorium.<BR>\n" );
document.write( "Since G = G, then:<BR>\n" );
document.write( " A + 21 = 3A Solve for A.<BR>\n" );
document.write( "2A = 21<BR>\n" );
document.write( "A = 10.5 The auditorium is 10.5 years old.\r<BR>\n" );
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document.write( "G = 3A <BR>\n" );
document.write( "G = 3(10.5)<BR>\n" );
document.write( "G = 31.5 The gym is 31.5 years old. </SPAN>\n" );
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