document.write( "Question 78550: I keep trying on this problem and I'm running out of time and sanity. Please for the love of God, help me. x5+24>3x3+8x2. I can't even figure out how to write it on the computer. That should be x to the power of 5, plus 24 > 3x to the power of 3 plus 8x squared. I understand that you need to bring everything over to equal 0. I have found one factor of it too, (x-2) but can't completely solve. Thanks so much! \n" ); document.write( "
Algebra.Com's Answer #56329 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E5%2B24%3E3x%5E3%2B8x%5E2\"
\n" ); document.write( "\"x%5E5-3x%5E3-8x%5E2%2B24%3E0\" Get all terms to one side
\n" ); document.write( "\"x%5E3%28x%5E2-3%29-8%28x%5E2-3%29%3E0\" Factor out the GCF
\n" ); document.write( "\"%28x%5E3-8%29%28x%5E2-3%29%3E0\" Combine like terms
\n" ); document.write( "\"%28x%5E3-8%29%28x%5E2-3%29=0\" Now make an equation\r
\n" ); document.write( "\n" ); document.write( "Set each factor equal to zero
\n" ); document.write( "\"x%5E3-8=0\"
\n" ); document.write( "\"%28x-2%29%28x%5E2%2B2x%2B4%29=0\" use the difference of cubes
\n" ); document.write( "Set x-2 equal to zero
\n" ); document.write( "\"x-2=0\"
\n" ); document.write( "\"x=2\"
\n" ); document.write( "Set \"x%5E2%2B2x%2B4\" equal to zero
\n" ); document.write( "\"x%5E2%2B2x%2B4=0\"
\n" ); document.write( "This cannot be factored further\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now set \"x%5E2-3\" equal to zero\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-3=0\"
\n" ); document.write( "\"x%5E2=3\"
\n" ); document.write( "\"x=0%2B-sqrt%283%29\"\r
\n" ); document.write( "\n" ); document.write( "So we have\r
\n" ); document.write( "\n" ); document.write( "\"x=sqrt%283%29\" or \"x=-sqrt%283%29\" or \"x=2\"\r
\n" ); document.write( "\n" ); document.write( "These are the points where \"x%5E5-3x%5E3-8x%5E2%2B24\" goes through the x-axis. These are the turning points from positive to negative or vice versa. In other words, at these points the graph will change from \"f%28x%29%3E0\" to \"f%28x%29%3C0\" or vice versa. So lets graph the equation \"y=x%5E5-3x%5E3-8x%5E2%2B24\"\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2Cx%5E5-3x%5E3-8x%5E2%2B24%29+\"\r
\n" ); document.write( "\n" ); document.write( "From the graph we can see that \"f%28x%29%3E0\" in the interval\r
\n" ); document.write( "\n" ); document.write( "[\"-sqrt%283%29\", \"sqrt%283%29\"] U [2,)\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );