document.write( "Question 927816: A chemist needs 18 L of a 10% alcohol solution but only has a 30% alcohol solution. How many liters each of the 30 solution and water should be mixed to make the desired 18 liters of a 10% solution? \n" ); document.write( "
Algebra.Com's Answer #563280 by stanbon(75887)\"\" \"About 
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A chemist needs 18 L of a 10% alcohol solution but only has a 30% alcohol solution. How many liters each of the 30 solution and water should be mixed to make the desired 18 liters of a 10% solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "water + water = water
\n" ); document.write( "0.70x + 1*(18-x) = 0.90*18
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\n" ); document.write( "70x + 100(18-x) = 90*18
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\n" ); document.write( "70x + 100*18 - 100x = 90*18
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\n" ); document.write( "-30x = -10*18
\n" ); document.write( "x = 6 L (amt of 30% solution needed)
\n" ); document.write( "18-x = 18-6 = 12 L (amt of water needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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