document.write( "Question 78581: grade B syrup sells for $1.35/L less then grade A syrup.if 80L of grade B syrup is mixed with 40 L of Grade A syrup, the resulting mixture will be worth $1.85/L. what is the unit price for the two grades of syrup? \n" ); document.write( "
Algebra.Com's Answer #56324 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! grade B syrup sells for $1.35/L less then grade A syrup.if 80L of grade B syrup is mixed with 40 L of Grade A syrup, the resulting mixture will be worth $1.85/L. what is the unit price for the two grades of syrup? \n" ); document.write( ": \n" ); document.write( "Let x = price of grade A syrup \n" ); document.write( "Then (x-1.35) = price of the grade B syrup \n" ); document.write( ": \n" ); document.write( "B stuff + A stuff = $1.85 stuff \n" ); document.write( "80(x-1.35) + 40x = 1.85(80+40) \n" ); document.write( ": \n" ); document.write( "80x - 108 + 40x = 1.85(120) \n" ); document.write( ": \n" ); document.write( "120x - 108 = 222 \n" ); document.write( ": \n" ); document.write( "120x = 222 + 108 \n" ); document.write( ": \n" ); document.write( "120x = 330 \n" ); document.write( ": \n" ); document.write( "x = 330/120 \n" ); document.write( ": \n" ); document.write( "x = $2.75, price of the A syrup \n" ); document.write( ": \n" ); document.write( "2.75 - 1.35 = $1.40 is the price of B syrup \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check: \n" ); document.write( "1.4(80) + 2.75(40) = 1.85(120) \n" ); document.write( " 112 + 110 = 222; confirms our solutions. \n" ); document.write( " |