document.write( "Question 927692: How many liters each of a 30% antifreeze solution and a 60% antifreeze solution must be mixed to make 10 L of a 36% anti-freeze solution? \n" ); document.write( "
Algebra.Com's Answer #563211 by rothauserc(4718)\"\" \"About 
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We have two equations to work with, let x be number of liters(L) of .30 solution, y be the number of L of .60 solution and 10*.36 = 3.6, then
\n" ); document.write( "x + y = 10
\n" ); document.write( ".30x + .60y = 3.60
\n" ); document.write( "solve first equation for x
\n" ); document.write( "x = 10 - y
\n" ); document.write( "substitute for x in second equation
\n" ); document.write( ".30(10-y) + .60y = 3.60
\n" ); document.write( "3-.30y +.60y = 3.60
\n" ); document.write( ".30y = .60
\n" ); document.write( "y = 2
\n" ); document.write( "therefore we have 2L of the .60 solution and 8L of the .30 solution\r
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