document.write( "Question 927730: Hello....I have 2 questions\r
\n" ); document.write( "\n" ); document.write( "1) y=x^2-6x+4 use quadratic formula to find the values of zeros.\r
\n" ); document.write( "\n" ); document.write( "Can someone help me with this? I believe I have found the vertex (3,-5) hoping this is correct?\r
\n" ); document.write( "\n" ); document.write( "2) Find the y and x intercepts of 2x^2-2x-12\r
\n" ); document.write( "\n" ); document.write( "Thank you!! \n" ); document.write( "
Algebra.Com's Answer #563210 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
1) y = x^2 -6x +4
\n" ); document.write( "using quadratic formula x = (-b + or - square root(b^2-4ac)) / 2a
\n" ); document.write( "x = (6 + square root(6^2 -4*1*4)) / (2*1) = 5.236067977
\n" ); document.write( "x = (6 - square root(6^2 -4*1*4)) / (2*1) = 0.763932023
\n" ); document.write( "x coordinate of vertex is -b/2a = 6/2 = 3
\n" ); document.write( "substitute for x in quadratic equation
\n" ); document.write( "y = 3^2 -6*3 +4 = -5
\n" ); document.write( "vertex is (3, -5)
\n" ); document.write( "2) y = 2x^2 -2x -12
\n" ); document.write( "if x = 0, then y = -12 which is the y intercept
\n" ); document.write( "to find x intercepts, set quadratic = 0
\n" ); document.write( "2x^2 -2x -12 = 0
\n" ); document.write( "divide both sides of = by 2
\n" ); document.write( "x^2 -x -6 = 0
\n" ); document.write( "this factors into
\n" ); document.write( "(x-3)*(x+2) = 0
\n" ); document.write( "x intercepts are 3 and -2
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