document.write( "Question 78559: A bicyclist rode into the country for 5h. In returning, her speed was 5mi/h faster and the trip took 4h. What was her speed each way? \n" ); document.write( "
Algebra.Com's Answer #56320 by patrickr(1)\"\" \"About 
You can put this solution on YOUR website!
Use D = rt (Distance = rate * time) to solve.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The distance is the same each way, a fact we will use later.
\n" ); document.write( "The time riding into the country and back are given, 5 and 4.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Her speed(rate)riding into the country is unknown so we assign it a variable: s
\n" ); document.write( "Her time riding into the country is 5 hours. \r
\n" ); document.write( "\n" ); document.write( "D1=rt , plug s (her speed) in for r and 5 in for time.\r
\n" ); document.write( "\n" ); document.write( "D1=s*5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Her speed(rate) returning is 5mi/h faster that her speed riding in: Thus s+5
\n" ); document.write( "Her time riding into the country is 4 hours. \r
\n" ); document.write( "\n" ); document.write( "D2=rt , plug s+5 (her speed) in for r and 4 in for time.\r
\n" ); document.write( "\n" ); document.write( "D2=(s+5)*4\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We know the two distances are the same, meaning D1=D2.\r
\n" ); document.write( "\n" ); document.write( "Substitute for D1 and D2 5s = 4(s+5)
\n" ); document.write( "Distribute the 4 5s = 4s+ 20
\n" ); document.write( "Subtract 4s from both sides s=20\r
\n" ); document.write( "\n" ); document.write( "Thus, her speed into the country was 20mi/h.
\n" ); document.write( "Her speed returning (5mi/h faster) was 25 mi/h.
\n" ); document.write( "
\n" );