document.write( "Question 927664: Graph the triangle with vertics a(0,24), b(-15,0), c(24,0). A) draw the three altitudes. Determine(algebraically) where the three altitudes intersect. \n" ); document.write( "

Algebra.Com's Answer #563189 by KMST(5328) $\"\"$ $\"About$

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BC is the horizontal line $\"y=0\"$ (the x-axis), and AC is the line $\"x%2By=24\"$ <---> $\"y=-x%2B24\"$ .
\n" ); document.write( "Since BC is the horizontal line $\"y=0\"$ (the x-axis), the altitude to BC is the vertical line passing through A, $\"x=0\"$ (the y-axis).
\n" ); document.write( "Since AC is a line with $\"slope=-1\"$ , the altitude to AC is the line with $\"slope=1\"$ passing through B(-15,0).
\n" ); document.write( "That line is $\"y-0=1%28x-%28-15%29%29\"$ <---> $\"y=x%2B15\"$ .
\n" ); document.write( "The three altitudes intersect at one point.
\n" ); document.write( "The point where the two altitudes found intersect can be found by solving the system
\n" ); document.write( " $\"system%28x=0%2Cy=x%2B15%29\"$ ---> $\"system%28x=0%2Cy=15%29\"$ .
\n" ); document.write( "That intersection is the point (0,15). \n" ); document.write( "

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