document.write( "Question 927665: Julia is twice as old as helen. In 4 years, the su of their ages will be 47. How old is each person \n" ); document.write( "
Algebra.Com's Answer #563152 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "Julia is twice as old as Helen:\r
\n" ); document.write( "\n" ); document.write( "\"J=2H\"...eq.1\r
\n" ); document.write( "\n" ); document.write( " In \"4\" years, the sum of their ages will be \"47\":\r
\n" ); document.write( "\n" ); document.write( "\"%28J%2B4%29%2B%28H%2B4%29=47\"....eq.2...substitute \"2H\" for \"J+\" from eq.1\r
\n" ); document.write( "\n" ); document.write( "\"2H%2B4%2BH%2B4=47\"...solve for \"H\"\r
\n" ); document.write( "\n" ); document.write( "\"3H%2B8=47\"\r
\n" ); document.write( "\n" ); document.write( "\"3H=47-8\"\r
\n" ); document.write( "\n" ); document.write( "\"3H=39\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28H=13%29\"\r
\n" ); document.write( "\n" ); document.write( "go back to eq.1 and find \"J\"\r
\n" ); document.write( "\n" ); document.write( "\"J=2H\"...eq.1\r
\n" ); document.write( "\n" ); document.write( "\"J=2%2A13\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28J=26%29\"\r
\n" ); document.write( "\n" ); document.write( "so, let's check the answer:\r
\n" ); document.write( "\n" ); document.write( "in \"4\" years \"J=30\" and \"H=17\", then their sum is \"30%2B17=47\"
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