document.write( "Question 927621: suppose that the manufacturer of a dvd player has found that, when the unit price is p dollars, the revenue r (in dollars) as a function of the price p is r(p)=-2.5p^2+550p. (a) for what price will the revenue be maximized? (b) what is the maximum revenue? \n" ); document.write( "
Algebra.Com's Answer #563108 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
When the form of the equation is
\n" ); document.write( "\"+f%28x%29+=+a%2Ax%5E2+%2B+b%2Ax+%2B+c+\", the
\n" ); document.write( "value of \"+x+\" where f(x) is a maximum
\n" ); document.write( "occurs at \"+-b%2F%282a%29+\"
\n" ); document.write( "------------------------
\n" ); document.write( "\"+r%28p%29+=+-2.5p%5E2+%2B+550p+\"
\n" ); document.write( "\"+p%5Bmax%5D+=+-550%2F%28-2.5%2A2%29+\"
\n" ); document.write( "\"+p%5Bmax%5D+=+550%2F5+\"
\n" ); document.write( "\"+p%5Bmax%5D+=+110+\"
\n" ); document.write( "(a)
\n" ); document.write( "At a price of $110 the revenue is maximized
\n" ); document.write( "-----------------
\n" ); document.write( "(b)
\n" ); document.write( "\"+r%28p%29+=+-2.5p%5E2+%2B+550p+\"
\n" ); document.write( "\"+r%5Bmax%5D+=+-2.5%2A110%5E2+%2B+550%2A110+\"
\n" ); document.write( "\"+r%5Bmax%5D+=+-30250+%2B+60500+\"
\n" ); document.write( "\"+r%5Bmax%5D+=+30250+\"
\n" ); document.write( "The maximum revenue is $30,250
\n" ); document.write( "--------------------------------
\n" ); document.write( "Here's a plot:
\n" ); document.write( "\"+graph%28+400%2C+400%2C+-50%2C+250%2C+-10000%2C+35000%2C+-2.5x%5E2+%2B+550x+%29+\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );