document.write( "Question 927403: Find the dimension and the maximum area of a rectangle if its perimeter is 36. \n" ); document.write( "
Algebra.Com's Answer #563081 by srinivas.g(540)\"\" \"About 
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perimeter =36
\n" ); document.write( "2(length+width)=36
\n" ); document.write( " length+width =36/2
\n" ); document.write( " length+width =18
\n" ); document.write( " possible alternatives:
\n" ); document.write( "length =17 width =1 area =17*1 = 17
\n" ); document.write( "length =16 width = 2 area =16*2 = 32
\n" ); document.write( "length =15 width =3 area = 15*3 =45
\n" ); document.write( "length =14 width = 4 area = 14*4 =56
\n" ); document.write( "length =13 width =5 area =13*5 =65
\n" ); document.write( "length =12 width =6 area =12*6 =72
\n" ); document.write( "length =11 width =7 area =11*7 =77
\n" ); document.write( "length =10 width =8 area =10*8 =80
\n" ); document.write( "length =9 width =9 area =9*9 =81
\n" ); document.write( "so maximum area = 81
\n" ); document.write( "dimensions = 9 x 9\r
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