document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78539>Question 78539</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you help me set up this problem and solve\r<BR>\n" );
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document.write( "the current I in electrical conductor varies inversely as the resistance R of the conductor.  suppose I is 0.2 amperes when the resistance is 200ohms. find the current when the resistance is 250ohms. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56308 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56308\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  the current I in electrical conductor varies inversely as the resistance R of the conductor.  suppose I is 0.2 amperes when the resistance is 200ohms. find the current when the resistance is 250ohms.<BR>\n" );
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document.write( "Use Ohm's law to find the voltage: E = I*R<BR>\n" );
document.write( "E = .2*200<BR>\n" );
document.write( "E = 40 v<BR>\n" );
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document.write( "I = E/R<BR>\n" );
document.write( "When 40 volts is applied to a resistance of 250 ohms<BR>\n" );
document.write( "I = 40/250<BR>\n" );
document.write( "I = .16 amps </SPAN>\n" );
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