document.write( "Question 78525: Solve each of the equations. Be sure to check your solutions.\r
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document.write( " √2y + 7+ 4=y
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document.write( "(The radical symbol is over the 2y+7) \n" );
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Algebra.Com's Answer #56307 by tutor_paul(519)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "First, get the terms under the radical on one side of the equation: \n" ); document.write( " \n" ); document.write( "Now, square both sides of the equation: \n" ); document.write( " \n" ); document.write( "Simplify, and put the equation into \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Factor this expression as follows: \n" ); document.write( " \n" ); document.write( "Note that this is a second order equation, so there are two roots. \n" ); document.write( "Equate each of the factors you just found to zero and solve for y. \n" ); document.write( "You get: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, this part is important... you need to plug these answers \n" ); document.write( "back in to the original problem to be sure they are not \"extraneous.\" \n" ); document.write( "An extraneous root is mathematically corrrect, but not a true answer.\r \n" ); document.write( "\n" ); document.write( "If you plug y=1 back into the original equation, you will see that the \n" ); document.write( "equation does NOT hold. Hence this is an extraneous root.\r \n" ); document.write( "\n" ); document.write( "If you plug y=9 back into the original equation, you will see that the \n" ); document.write( "equation DOES hold. so that one is your answer. \n" ); document.write( " |