document.write( "Question 78525: Solve each of the equations. Be sure to check your solutions.\r
\n" ); document.write( "\n" ); document.write( " √2y + 7+ 4=y
\n" ); document.write( "(The radical symbol is over the 2y+7)
\n" ); document.write( "

Algebra.Com's Answer #56307 by tutor_paul(519)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%28%282%2Ay%29%2B7%29%2B4=y\"
\n" ); document.write( "First, get the terms under the radical on one side of the equation:
\n" ); document.write( "\"sqrt%28%282%2Ay%29%2B7%29=y-4\"
\n" ); document.write( "Now, square both sides of the equation:
\n" ); document.write( "\"%282%2Ay%29%2B7=%28y-4%29%5E2\"
\n" ); document.write( "Simplify, and put the equation into \"ax%5E2%2Bbx%2Bc=0\" form:
\n" ); document.write( "\"%282%2Ay%29%2B7=y%5E2-%288%2Ay%29%2B16\"
\n" ); document.write( "\"y%5E2-%2810%2Ay%29%2B9=0\"
\n" ); document.write( "Factor this expression as follows:
\n" ); document.write( "\"%28y-1%29%2A%28y-9%29=0\"
\n" ); document.write( "Note that this is a second order equation, so there are two roots.
\n" ); document.write( "Equate each of the factors you just found to zero and solve for y.
\n" ); document.write( "You get:
\n" ); document.write( "\"y=1\" and \"y=9\"\r
\n" ); document.write( "\n" ); document.write( "Now, this part is important... you need to plug these answers
\n" ); document.write( "back in to the original problem to be sure they are not \"extraneous.\"
\n" ); document.write( "An extraneous root is mathematically corrrect, but not a true answer.\r
\n" ); document.write( "\n" ); document.write( "If you plug y=1 back into the original equation, you will see that the
\n" ); document.write( "equation does NOT hold. Hence this is an extraneous root.\r
\n" ); document.write( "\n" ); document.write( "If you plug y=9 back into the original equation, you will see that the
\n" ); document.write( "equation DOES hold. so that one is your answer.
\n" ); document.write( "
\n" );