document.write( "Question 927455: Mr. Sanchez makes a business trip from his house to the city in 2 hours. One hour later, he returns home in heavy traffic at a rate of 20 kph(kilometers per hour) less than his going rate. If Mr. Sanchez was gone a total of 6 hours, how fast did he travel on each of the trip? \n" ); document.write( "
Algebra.Com's Answer #562967 by TimothyLamb(4379)\"\" \"About 
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s = d/t
\n" ); document.write( "---
\n" ); document.write( "outbound:
\n" ); document.write( "t = 2 hrs
\n" ); document.write( "x = outbound speed
\n" ); document.write( "x = d/2
\n" ); document.write( "d = 2x
\n" ); document.write( "---
\n" ); document.write( "return:
\n" ); document.write( "he's in the city for 1 hour (not traveling during that 1 hr)
\n" ); document.write( "t = 6 - 2 - 1 = 3 hrs
\n" ); document.write( "y = return speed
\n" ); document.write( "y = x - 20
\n" ); document.write( "y = d/3
\n" ); document.write( "d = 3y
\n" ); document.write( "---
\n" ); document.write( "2x = 3y
\n" ); document.write( "2x = 3(x - 20)
\n" ); document.write( "2x = 3x - 60
\n" ); document.write( "x = 60
\n" ); document.write( "y = x - 20
\n" ); document.write( "y = 60 - 20
\n" ); document.write( "y = 40
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "x = outbound speed = 60 kph
\n" ); document.write( "y = return speed = 40 kph
\n" ); document.write( "---
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