document.write( "Question 927356: A city is interested in estimating the amount of time children spend on the internet
\n" );
document.write( "each day. It is known the the time spent follows a normal distribution with standard
\n" );
document.write( "deviation 35 minutes.
\n" );
document.write( "(a) How many children would be needed to estimate the true mean amount of time
\n" );
document.write( "spent on the internet to within 19 minutes with 95% confidence?
\n" );
document.write( "(b) How many children would be needed to estimate the true mean amount of time
\n" );
document.write( "spent on the internet to within 19 minutes with 96% confidence?
\n" );
document.write( "(c) Only using your answer in (a), how many children are needed to estimate the
\n" );
document.write( "true mean amount of time spent on the internet to within 18 minutes with 95%
\n" );
document.write( "confidence?
\n" );
document.write( "(d) What happened to your sample size from part (a) to part (b)? Explain.
\n" );
document.write( "(e) Create a 90% confidence interval for the true mean amount of time spent on the
\n" );
document.write( "internet.
\n" );
document.write( "(f) Interpret your interval in (e).
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #562933 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! a) n = (zSD/ME)^2 = (1.96*35/19)^2 = 13.0359 0r 14 \n" ); document.write( "b) n = (zSD/ME)^2 = (2.0537*35/19)^2 = 14.312 0r 15 \n" ); document.write( "c) n > 14, n = (zSD/ME)^2 = (1.96*35/18)^2 = 14.5246 0r 15 \n" ); document.write( "d) Sample size part b is Larger due to increased confidence Level. \n" ); document.write( "e) ME = 1.645(12) = 57.575 (round as directed) \n" ); document.write( " \n" ); document.write( " |