document.write( "Question 927335: The width of a rectangle is five times its lenghy. If the area of the rectangle is 45, then what is the perimeter of the rectangle?\r
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document.write( "a) 3
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document.write( "b)9
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document.write( "c)15
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document.write( "d)18
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document.write( "e)36 \n" );
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Algebra.Com's Answer #562902 by srinivas.g(540)![]() ![]() You can put this solution on YOUR website! Let length of rectangle be l \n" ); document.write( "Width = 5 times the length \n" ); document.write( " width = 5l \n" ); document.write( " area = 45 \n" ); document.write( " length x width =45 \n" ); document.write( "l x 5l =45 \n" ); document.write( " \n" ); document.write( " divide with 5 on both sides \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " square root on both sides \n" ); document.write( " \n" ); document.write( " l=3 \n" ); document.write( " width = 5x3 = 15 \n" ); document.write( "Perimeter = 2(length+width) \n" ); document.write( " =2(3+15) \n" ); document.write( " =2*18 \n" ); document.write( " =36 \n" ); document.write( "Result : Perimeter = 36 \n" ); document.write( " \n" ); document.write( " |