document.write( "Question 927335: The width of a rectangle is five times its lenghy. If the area of the rectangle is 45, then what is the perimeter of the rectangle?\r
\n" ); document.write( "\n" ); document.write( "a) 3
\n" ); document.write( "b)9
\n" ); document.write( "c)15
\n" ); document.write( "d)18
\n" ); document.write( "e)36
\n" ); document.write( "

Algebra.Com's Answer #562902 by srinivas.g(540)\"\" \"About 
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Let length of rectangle be l
\n" ); document.write( "Width = 5 times the length
\n" ); document.write( " width = 5l
\n" ); document.write( " area = 45
\n" ); document.write( " length x width =45
\n" ); document.write( "l x 5l =45
\n" ); document.write( " \"+5l%5E2+=45\"
\n" ); document.write( " divide with 5 on both sides
\n" ); document.write( "\"+5+l%5E2%2F5=+45%2F5\"
\n" ); document.write( " \"+l%5E2+=9\"
\n" ); document.write( " square root on both sides
\n" ); document.write( " \"+sqrt%28l%5E2%29+=sqrt%289%29\"
\n" ); document.write( " l=3
\n" ); document.write( " width = 5x3 = 15
\n" ); document.write( "Perimeter = 2(length+width)
\n" ); document.write( " =2(3+15)
\n" ); document.write( " =2*18
\n" ); document.write( " =36
\n" ); document.write( "Result : Perimeter = 36
\n" ); document.write( "
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