document.write( "Question 78472: The figure shows the graph of the polynomial function y=f(x). For which of th values k=0,1,2,or 3 will the equation f(x) = k have complex roots?
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\n" ); document.write( "I am not sure how to draw the graph to show what it looks like so I will try to explain it. The line comes up from the bottom of quadrant 3 and it goes to the right of (-1,-1)and continues up to (0,2)it then curves down thru (1,0)to (2,-2)and then curves up to just left of (3,0)and keeps going upward.
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Algebra.Com's Answer #56277 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
It sounds like you are describing a cubic ( a function with \"x%5E3\" in it). Since I cannot see the graph, simply look at the graph and see if it intersects with these lines:\r
\n" ); document.write( "\n" ); document.write( "\"y=0\", \"y=1\", \"y=2\", \"y=3\"\r
\n" ); document.write( "\n" ); document.write( "If it intersects in 3 places it will have 3 real roots. If it intersects at 1 place, then it will have 1 real root and 2 complex root. So if the graph intersects with say \"y=1\" at one spot, then it will have 2 complex roots.
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