document.write( "Question 927115: A company manufacturing light bulbs claims that an average light bulb lasts 300
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document.write( "days. A potential customer randomly selects 15 bulbs for testing. The sampled bulbs
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document.write( "last an average of 290 days, with a standard deviation of 50 days. If the company’s
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document.write( "claim were true, what is the probability that 15 randomly selected bulbs would have
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document.write( "an average life of no more than 290 days? \n" );
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Algebra.Com's Answer #562764 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! mean = 300 \n" ); document.write( "P(x ≤ 290) = P( z < -10/(50/sqrt(15)) =P(z < -.7746) \n" ); document.write( "Using a TI calculator 0r similarly a Casio fx-115 ES plus \n" ); document.write( "P(x ≤ 290) =P(z < -.7746) = normalcdf(-100, -.7746)= .2193 0r 21.93% \n" ); document.write( " |