document.write( "Question 927131: The area of an equilateral triangle is 125 sq. cm. Find its altitude?
\n" ); document.write( "i need help coz i dont know how to answer it. my teacher didnt discuss this part :(
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Algebra.Com's Answer #562715 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "The area of an equilateral triangle is 125 sq. cm.
\n" ); document.write( "Find its altitude:
\n" ); document.write( "I. Altitude bisects Base
\n" ); document.write( "II. 30-60-90 Triangle is formed: Ratio of Sides: 1 : √3 : 2
\n" ); document.write( "III. 30-60-90 Triangle formed: sides: s/2, (s/2)√3, s
\n" ); document.write( "........
\n" ); document.write( "A = \"%281%2F2%29bh+=+%281%2F2%29%28s%29%28s%2Asqrt%283%29%2F2%29\"
\n" ); document.write( "A = \"%281%2F2%29%28s%29%28s%2Asqrt%283%29%2F2%29+=+125+cm%5E2\"
\n" ); document.write( "A = (1/4)s^2 √3 = 125
\n" ); document.write( "s =\"+sqrt%28+4%2A125%2Fsqrt%283%29%29\" = 17 rounded
\n" ); document.write( "h =\"+17sqrt%283%29%2F2\" = 8.5√3 = 14.7 rounded\r
\n" ); document.write( "\n" ); document.write( "and...checking
\n" ); document.write( "A = \"%281%2F2%29bh+=+%281%2F2%29%2817%29%2A14.7+\" = 125 rounded
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