document.write( "Question 927114: SHOW THAT:\r
\n" ); document.write( "\n" ); document.write( "1 over TAN A (1st fraction) + sin A OVER 1 + cos A (2nd fraction) = 1 over sin A (3rd fraction)\r
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Algebra.Com's Answer #562685 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"1%2Ftan%28A%29%2Bsin%28A%29%2F%281+%2B+cos+A%29+=1%2Fsin%28A%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%28sin%28A%29%2Fcos%28A%29%29%2Bsin%28A%29%2F%281+%2B+cos+A%29+=1%2Fsin%28A%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28A%29%2Fsin%28A%29%2Bsin%28A%29%2F%281+%2B+cos+A%29+=1%2Fsin%28A%29\"\r
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\n" ); document.write( "\n" ); document.write( "...since \"sin%5E2%28A%29=1-cos%5E2%28A%29\", we have\r
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\n" ); document.write( "\n" ); document.write( "\"%28cos%28A%29++%2B1%29%2F%28sin%28A%29%281+%2B+cos+A%29%29+=1%2Fsin%28A%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2Fsin%28A%29+=1%2Fsin%28A%29\"
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