document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=927076>Question 927076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Evaluate the expression: ln(e^-13)<BR>\n" );
document.write( "Evaluate the expression: Log1000<BR>\n" );
document.write( "Expand: ln(5x^2)<BR>\n" );
document.write( "Condense: log14+2logY-logX<BR>\n" );
document.write( "Write in exponential form: ln(2.226)=0.8\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #562670 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=562670\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Evaluate the expression: ln(e^-13)=-13 (base raised to a power=power)<BR>\n" );
document.write( "Evaluate the expression: Log1000=3 (base(10)raised to log of number(3)=number(1000)<BR>\n" );
document.write( "Expand: ln(5x^2)=ln(5)+2*ln(x)<BR>\n" );
document.write( "Condense: log14+2logY-logX=log(14*y^2/x)<BR>\n" );
document.write( "Write in exponential form: ln(2.226)=0.8=e^(0.8)=2.226 </SPAN>\n" );
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