document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=926959>Question 926959</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The product of two consecutive even integers is 56  less than 8  times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first.\r<BR>\n" );
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document.write( "I get that the first number would be x, and the second would be x+2; so the first portion of the equation would be x(x+2). It is the second part, 56 less than 8 times their sum. HELP! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #562616 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=562616\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write as We Read<BR>\n" );
document.write( "x(x+2) = 8(x + x+2) - 56  <BR>\n" );
document.write( "x^2 + 2x = 16x + 16 - 56<BR>\n" );
document.write( "x^2 -14x + 40 = 0<BR>\n" );
document.write( "(x - 4)(x - 10) = 0<BR>\n" );
document.write( "x =  4, 10<BR>\n" );
document.write( "the two consecutive even integers are: (4, 6)  and (10, 12)<BR>\n" );
document.write( ".....<BR>\n" );
document.write( "and..checking<BR>\n" );
document.write( "24 = 8(10) - 56 = 24<BR>\n" );
document.write( "120 = 8( 22) - 56 = 120 </SPAN>\n" );
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