document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=926936>Question 926936</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose that the population of a small town is 32000 at the beginning of 2005 and the city council assumes that the population size t years later can be estimated by the equation p(t)=32000e^0.05t Approximately when will the city have a population of 64000? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #562589 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=562589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> suppose that the population of a small town is 32000 at the beginning of 2005 and the city council assumes that the population size t years later can be estimated by the equation p(t)=32000e^0.05t Approximately when will the city have a population of 64000?<BR>\n" );
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document.write( "Solve::<BR>\n" );
document.write( "64000 = 32000*e^(0.05t)<BR>\n" );
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document.write( "e^(0.05t) = 2<BR>\n" );
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document.write( "Take the natural log of both sides to get:<BR>\n" );
document.write( "0.05t = ln(2)<BR>\n" );
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document.write( "t = ln(2)/0.05<BR>\n" );
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document.write( "t = 13.86 years<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "----------------- </SPAN>\n" );
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