document.write( "Question 926884: how would you find the perimeter and area of a shape with the coordinates (-3,4), (1,5), (2,1), and (-2,0)?
\n" ); document.write( "HELP ME PLEEAASEEE!!!!!!
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Algebra.Com's Answer #562557 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "plot points:\r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "find the distance:\r
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Distance Formula

\n" ); document.write( "
\n" ); document.write( " The first point is (x1,y1). The second point is (x2,y2)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the first point is (-2, 0), we can say (x1, y1) = (-2, 0)
\n" ); document.write( " So \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+0\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the second point is (-3, 4), we can also say (x2, y2) = (-3, 4)
\n" ); document.write( " So \"x%5B2%5D+=+-3\", \"y%5B2%5D+=+4\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Put this all together to get: \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+0\", \"x%5B2%5D+=+-3\", and \"y%5B2%5D+=+4\"
\n" ); document.write( "
\n" ); document.write( " --------------------------------------------------------------------------------------------
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now use the distance formula to find the distance between the two points (-2, 0) and (-3, 4)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28-2+-+%28-3%29%29%5E2+%2B+%280+-+4%29%5E2%29\" Plug in \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+0\", \"x%5B2%5D+=+-3\", and \"y%5B2%5D+=+4\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28-2+%2B+3%29%5E2+%2B+%280+-+4%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%281%29%5E2+%2B+%28-4%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%281+%2B+16%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%2817%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+4.12310562561766\"
\n" ); document.write( "
\n" ); document.write( " ==========================================================
\n" ); document.write( "
\n" ); document.write( " Answer:
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " The distance between the two points (-2, 0) and (-3, 4) is exactly \"sqrt%2817%29\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " The approximate distance between the two points is about 4.12310562561766 units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So again,
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Exact Distance: \"sqrt%2817%29\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Approximate Distance: \"4.12310562561766\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Distance Formula

\n" ); document.write( "
\n" ); document.write( " The first point is (x1,y1). The second point is (x2,y2)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the first point is (1, 5), we can say (x1, y1) = (1, 5)
\n" ); document.write( " So \"x%5B1%5D+=+1\", \"y%5B1%5D+=+5\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the second point is (-3, 4), we can also say (x2, y2) = (-3, 4)
\n" ); document.write( " So \"x%5B2%5D+=+-3\", \"y%5B2%5D+=+4\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Put this all together to get: \"x%5B1%5D+=+1\", \"y%5B1%5D+=+5\", \"x%5B2%5D+=+-3\", and \"y%5B2%5D+=+4\"
\n" ); document.write( "
\n" ); document.write( " --------------------------------------------------------------------------------------------
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now use the distance formula to find the distance between the two points (1, 5) and (-3, 4)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%281+-+%28-3%29%29%5E2+%2B+%285+-+4%29%5E2%29\" Plug in \"x%5B1%5D+=+1\", \"y%5B1%5D+=+5\", \"x%5B2%5D+=+-3\", and \"y%5B2%5D+=+4\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%281+%2B+3%29%5E2+%2B+%285+-+4%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%284%29%5E2+%2B+%281%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%2816+%2B+1%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%2817%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+4.12310562561766\"
\n" ); document.write( "
\n" ); document.write( " ==========================================================
\n" ); document.write( "
\n" ); document.write( " Answer:
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " The distance between the two points (1, 5) and (-3, 4) is exactly \"sqrt%2817%29\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " The approximate distance between the two points is about 4.12310562561766 units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So again,
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Exact Distance: \"sqrt%2817%29\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Approximate Distance: \"4.12310562561766\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Distance Formula

\n" ); document.write( "
\n" ); document.write( " The first point is (x1,y1). The second point is (x2,y2)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the first point is (1, 5), we can say (x1, y1) = (1, 5)
\n" ); document.write( " So \"x%5B1%5D+=+1\", \"y%5B1%5D+=+5\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the second point is (2, 1), we can also say (x2, y2) = (2, 1)
\n" ); document.write( " So \"x%5B2%5D+=+2\", \"y%5B2%5D+=+1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Put this all together to get: \"x%5B1%5D+=+1\", \"y%5B1%5D+=+5\", \"x%5B2%5D+=+2\", and \"y%5B2%5D+=+1\"
\n" ); document.write( "
\n" ); document.write( " --------------------------------------------------------------------------------------------
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now use the distance formula to find the distance between the two points (1, 5) and (2, 1)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%281+-+2%29%5E2+%2B+%285+-+1%29%5E2%29\" Plug in \"x%5B1%5D+=+1\", \"y%5B1%5D+=+5\", \"x%5B2%5D+=+2\", and \"y%5B2%5D+=+1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28-1%29%5E2+%2B+%284%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%281+%2B+16%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%2817%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+4.12310562561766\"
\n" ); document.write( "
\n" ); document.write( " ==========================================================
\n" ); document.write( "
\n" ); document.write( " Answer:
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " The distance between the two points (1, 5) and (2, 1) is exactly \"sqrt%2817%29\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " The approximate distance between the two points is about 4.12310562561766 units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So again,
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Exact Distance: \"sqrt%2817%29\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Approximate Distance: \"4.12310562561766\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Distance Formula

\n" ); document.write( "
\n" ); document.write( " The first point is (x1,y1). The second point is (x2,y2)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the first point is (-2, 0), we can say (x1, y1) = (-2, 0)
\n" ); document.write( " So \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+0\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the second point is (2, 1), we can also say (x2, y2) = (2, 1)
\n" ); document.write( " So \"x%5B2%5D+=+2\", \"y%5B2%5D+=+1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Put this all together to get: \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+0\", \"x%5B2%5D+=+2\", and \"y%5B2%5D+=+1\"
\n" ); document.write( "
\n" ); document.write( " --------------------------------------------------------------------------------------------
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now use the distance formula to find the distance between the two points (-2, 0) and (2, 1)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28-2+-+2%29%5E2+%2B+%280+-+1%29%5E2%29\" Plug in \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+0\", \"x%5B2%5D+=+2\", and \"y%5B2%5D+=+1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28-4%29%5E2+%2B+%28-1%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%2816+%2B+1%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%2817%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+4.12310562561766\"
\n" ); document.write( "
\n" ); document.write( " ==========================================================
\n" ); document.write( "
\n" ); document.write( " Answer:
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " The distance between the two points (-2, 0) and (2, 1) is exactly \"sqrt%2817%29\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " The approximate distance between the two points is about 4.12310562561766 units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So again,
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Exact Distance: \"sqrt%2817%29\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Approximate Distance: \"4.12310562561766\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "since all same, means you have a square;\r
\n" ); document.write( "\n" ); document.write( "so, the perimeter will be \"P=4d=4%284.123%29=16.492\"\r
\n" ); document.write( "\n" ); document.write( " and area \"A=d%5E2=%284.123%29%5E2=16.999\"\r
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