document.write( "Question 926883: it is known that the variance of a population equals 1936. A random sample of 121 has been taken from the population. there is a 0.95 probability that the sample mean will provide a margin of error of? \n" ); document.write( "
Algebra.Com's Answer #562546 by ewatrrr(24785)\"\" \"About 
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ME = 1.96 sqrt(1936/121) = 1.96(4) = 7.84
\n" ); document.write( "95% chance ME = ± 7.84
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