document.write( "Question 926798: Ray is 4 times older than Nica. Ten years from now, he will be twice as old as she is. How old is she now? \n" ); document.write( "
Algebra.Com's Answer #562528 by Alan3354(69443)\"\" \"About 
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Ray is 4 times older than Nica. Ten years from now, he will be twice as old as she is. How old is she now?
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\n" ); document.write( "Now:
\n" ); document.write( "R = 5N
\n" ); document.write( "In 10 years:
\n" ); document.write( "R + 10 = 2*(N+10)
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\n" ); document.write( "5N+10 = 2N+20
\n" ); document.write( "3N = 10
\n" ); document.write( "N = 3 1/3 years
\n" ); document.write( "R = 16 2/3 years
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\n" ); document.write( "The solution is not integers, as expected.
\n" ); document.write( "The writer of the problem thinks 4 times older = 4 times as old. It doesn't.
\n" ); document.write( "Is 1 time older the same age? If so, why is it called older?
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\n" ); document.write( "4 times older --> an increase in age of 400% --> 5 times as old.
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