document.write( "Question 78447This question is from textbook Advanced Algebra
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document.write( ": The Problem is (15/x)+((9x-7)/(x+2))=9. I understand now how to do the simple equations but i just get confused when i see long denominators. I don't know how to find the LCM very well. \n" );
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Algebra.Com's Answer #56252 by stanbon(75887) ![]() You can put this solution on YOUR website! The Problem is (15/x)+((9x-7)/(x+2))=9. I understand now how to do the simple equations but i just get confused when i see long denominators. I don't know how to find the LCM very well. \n" ); document.write( "---------------- \n" ); document.write( "Your denominators are x, (x+2), and 1. \n" ); document.write( "The lcm must contain each of the factors in their highest power. \n" ); document.write( "For your problem that is x(x+2) \n" ); document.write( "-------------- \n" ); document.write( "So, multiply thru the equation by x(x+2) to get rid of the denominators: \n" ); document.write( "15(x+2) + (9x-7)x =9x(x+2) \n" ); document.write( "15x+30 + 9x^2-7x = 9x^2+18x \n" ); document.write( "8x+30=18x \n" ); document.write( "10x=30 \n" ); document.write( "x=3 \n" ); document.write( "---------- \n" ); document.write( "Checking you get: 15/3 + 20/5 = 9-----true \n" ); document.write( "========== \n" ); document.write( "Solution: x=3 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |