document.write( "Question 926839: If one root of the equation ax^2+bx+c=0 is 2+√3 , then what is the other root if a, b and c are integers? Please help someone?? \n" ); document.write( "
Algebra.Com's Answer #562514 by ewatrrr(24785)\"\" \"About 
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ax^2+bx+c=0
\n" ); document.write( "one root is 2+√3
\n" ); document.write( "Then... the other root is 2-√3
\n" ); document.write( "x - (2+√3 ))(x - (2-√3)) = 0
\n" ); document.write( "x^2 - (4+1) = 0
\n" ); document.write( "x^2 -4x + 7 = 0
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"x+=+%284%2B-+sqrt%28+12+%29%29%2F%282%29+\"
\n" ); document.write( "\"x+=+%284%2B-+sqrt%28+4%2A3+%29%29%2F%282%29+\"
\n" ); document.write( "\"x+=+%284%2B-+2sqrt%283+%29%29%2F%282%29+\"
\n" ); document.write( "\"x+=+%282%2B-+sqrt%283+%29%29\"
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