document.write( "Question 926832: Let f(x) = -3x(x+2)^2 (x-4)^3\r
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document.write( "Perform the Leading Coefficient Test to determine the end behavior of the function. List a^n and n and explain how they lead to your conclusion.\r
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document.write( "(Identify all zeros) \n" );
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Algebra.Com's Answer #562509 by Theo(13342)![]() ![]() You can put this solution on YOUR website! your equation is: \n" ); document.write( "f(x) = -3x(x+2)^2 (x-4)^3 \n" ); document.write( "(x+2)^2 will have a leading term of x^2 \n" ); document.write( "(x-4)^3 will have a leading term of x^3 \n" ); document.write( "x * x^2 * x^3 = x^6 \n" ); document.write( "your leading exponent is x^6 \n" ); document.write( "your leading coefficient will be negative because you have 2 leading coefficients that are positive times 1 leading coefficient that is negative to get a negative leading coefficient because a negative times 2 positives is equal to a negative. \n" ); document.write( "your leading term have an even exponent and your leading coefficient is negative so the equation will fall to the left and fall to the right. \n" ); document.write( "your zeroes are x = 0, x = -2, x = 4 \n" ); document.write( "the graph of the equation will touch the x-axis at x = -2 and cross the x-axis at x = 0 and x = 4 \n" ); document.write( "this is because the exponent of the (x+2)^2 term is even and the exponent of the (x-4)^3 term and the x term are both odd. \n" ); document.write( "the graph of your equation looks like this: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a reference that can help you understand just what went on.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut35_polyfun.htm \n" ); document.write( " \n" ); document.write( " |