document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=926816>Question 926816</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A regression analysis between the volume of a type of drug produced and the weight of a particular ingredient used in a pharmaceutical process shows that y = -100 + 0.3x, where x = kilograms of ingredient and y = litres of drug. How much ingredient would be used to produce 100 litres of the drug? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #562506 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=562506\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y equals -100 + .3x<BR>\n" );
document.write( "x = kilograms of ingredients.<BR>\n" );
document.write( "y = liters of drug.<BR>\n" );
document.write( "how much ingredient would be used to produce 100 liters of the drug?<BR>\n" );
document.write( "replace y with 100 and solve for x.<BR>\n" );
document.write( "y = -100 + .3x becomes:<BR>\n" );
document.write( "100 = -100 + .3x<BR>\n" );
document.write( "add 100 to both sides of the equation to get:<BR>\n" );
document.write( "200 = .3x<BR>\n" );
document.write( "divide both sides of the equation by .3 to get:<BR>\n" );
document.write( "666.6666666...7 kilograms of ingredients.<BR>\n" );
document.write( "this can be translated to 666 and 2/3 kilograms of ingredients.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );