document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=926816>Question 926816</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A regression analysis between the volume of a type of drug produced and the weight of a particular ingredient used in a pharmaceutical process shows that y = -100 + 0.3x, where x = kilograms of ingredient and y = litres of drug. How much ingredient would be used to produce 100 litres of the drug? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #562505 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=562505\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = -100 + 0.3x<BR>\n" );
document.write( "where x = kilograms of ingredient and y = litres of drug<BR>\n" );
document.write( "y = 100L<BR>\n" );
document.write( "100 = -100 + .3x<BR>\n" );
document.write( "200/.3 = x = 666  2/3 kg </SPAN>\n" );
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