document.write( "Question 926826: Two opposite sides of a square with length x are increased by 3 units each and the other two opposite sides are decreased by 3 units each. If the area of the resulting rectangle is 27 units, what would be the width of the rectangle?
\n" ); document.write( "Hint: area of rectangle = length × width \n" ); document.write( "
Algebra.Com's Answer #562500 by Theo(13342)\"\" \"About 
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x equals the length of the side of the square.
\n" ); document.write( "length of the rectangle is equal to x+3
\n" ); document.write( "width of the rectangle is equal to x-3
\n" ); document.write( "area of the rectangle is equal to length * width which becomes:
\n" ); document.write( "(x-3) * (x+3) = 27
\n" ); document.write( "multiply the factors together and you get:
\n" ); document.write( "x^2 - 9 = 27
\n" ); document.write( "add 9 to both sides of the equation to get:
\n" ); document.write( "x^2 = 36
\n" ); document.write( "take the square root of both sides of the equqtion to get:
\n" ); document.write( "x = plus or minus 6
\n" ); document.write( "minus is no good.
\n" ); document.write( "x = 6
\n" ); document.write( "x+3 = 9
\n" ); document.write( "x-3 = 3
\n" ); document.write( "length of the rectangle is 9
\n" ); document.write( "width of the rectangle is 3.\r
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