document.write( "Question 926768: log(x^-2x)=log35 \n" ); document.write( "

Algebra.Com's Answer #562485 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"x%5E2-2x=35\"$
\n" ); document.write( " $\"x%5E2-2x-35=0\"$
\n" ); document.write( " $\"%28x-7%29%28x%2B5%29=0\"$
\n" ); document.write( "Two solutions:
\n" ); document.write( " $\"x-7=0\"$
\n" ); document.write( " $\"x=7\"$
\n" ); document.write( "and
\n" ); document.write( " $\"x%2B5=0\"$
\n" ); document.write( " $\"x=-5\"$
\n" ); document.write( " \n" ); document.write( "

\n" );