document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78424>Question 78424</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0130501832/algebrahomeworkh>Advanced Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Ok... the problem is (1/x)-(1/3)=(6/x^2). The instructions are to Solve the equation. I tried the problem and i got No Solution. I'm not really sure if this is the correct answer. I don't really understand this area in the chapter very much at all. Your help would be very Appreciated! Thanks!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56247 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1/x)-(1/3)=(6/x^2)<BR>\n" );
document.write( "The lcm is 3x^2.<BR>\n" );
document.write( "Multiply thru by 3x^2 to get:<BR>\n" );
document.write( "3x-x^2=18<BR>\n" );
document.write( "x^2-3x+18=0<BR>\n" );
document.write( "(x-6)(x+3)=0<BR>\n" );
document.write( "x=6 or x=-3<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Checking these answers:<BR>\n" );
document.write( "If x=6: 1/6-2/6=6/36------false<BR>\n" );
document.write( "If x=-3: -1/3-1/3=6/9-----false<BR>\n" );
document.write( "Therefore No Solution.<BR>\n" );
document.write( "===========Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );