document.write( "Question 926771: a pair of dice are tossed twice . what is the probability of getting a total of 7 & 11?
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Algebra.Com's Answer #562457 by Edwin McCravy(20055)\"\" \"About 
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document.write( "There are 6 ways to roll 7: \r\n" );
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document.write( "(1,6) (2,5) (3,4) (4,3) (5,2) (6.1).\r\n" );
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document.write( "There are 2 ways to get 11: \r\n" );
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document.write( "(6,5) (5,6).\r\n" );
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document.write( "There are 36 ways to roll a pair of dice:\r\n" );
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document.write( "(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)\r\n" );
document.write( "(2,1) (2,2) (2,3) (2,4) (2,5) (2,6) \r\n" );
document.write( "(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) \r\n" );
document.write( "(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) \r\n" );
document.write( "(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) \r\n" );
document.write( "(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)  \r\n" );
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document.write( "The probablity of rolling a 7 is \"6%2F36\" or \"1%2F6\".\r\n" );
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document.write( "The probablity of rolling a 11 is \"2%2F36\" or \"1%2F18\".\r\n" );
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document.write( "Not being a craps shooter, I am ignorant of the rules of the game J.\r\n" );
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document.write( "So I don't know whether we must get a 7 first and an 11 second,\r\n" );
document.write( "or whether it will be acceptable to get an 11 first and a 7 second.\r\n" );
document.write( "So I'll do it both eway.\r\n" );
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document.write( "(a) assuming we MUST get 7 first and 11 second:\r\n" );
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document.write( "P(7 first AND 11 second) = P(7 first) × P(11 second) = \"%281%2F6%29%281%2F18%29\" = \"1%2F108\"\r\n" );
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document.write( "(b) assuming we can get 7 first and 11 second OR get 11 first and 7 second:\r\n" );
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document.write( "P(7 first AND 11 second) OR (11 first AND 7 second) = \r\n" );
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document.write( "P(7 first) × P(11 second) + P(11 first)×P(7 second) = \r\n" );
document.write( "\"%281%2F6%29%2A%281%2F18%29%2B%281%2F18%29%281%2F6%29\" = \"1%2F108%2B1%2F108\" = \"2%2F108\" = \"1%2F54\"\r\n" );
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document.write( "Edwin
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