document.write( "Question 78381: Crafts. A solar collector is 2.5m long by 2.0m wide. It is held in place by a frame of uniform width around its outside edge. If the exposed collector area is 2.5m^2, what is the width of the frame, to the nearest tenth of a centimeter? \n" ); document.write( "
Algebra.Com's Answer #56244 by checkley75(3666)\"\" \"About 
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(2.5-2X)(2.0-2X)=2.5
\n" ); document.write( "5-4X-5X+4X^2=2.5
\n" ); document.write( "4X^2-9X+5-2.5=0
\n" ); document.write( "4X^2-9X+2.5=0
\n" ); document.write( "USING THE QUADRATIC EQUATIION WE GET:
\n" ); document.write( "X=(9+-SQRT[-9^2-4*4*2.5])/2*4
\n" ); document.write( "X=(9+-SQRT[81-40])/8
\n" ); document.write( "X=(9+-SQRT41)/8
\n" ); document.write( "X=(9+-6.4)/8
\n" ); document.write( "X=(9+6.4)/8
\n" ); document.write( "X=15.4/8
\n" ); document.write( "X=1.925 NON ANSWER.
\n" ); document.write( "X=(9-6.4)/8
\n" ); document.write( "X=2.6/8
\n" ); document.write( "X=.325 m. ANSWER.
\n" ); document.write( "PROOF
\n" ); document.write( "(2.5-2*.325)(2-2*.325)=2.5
\n" ); document.write( "(2.5-.65)(2-.65)=2.5
\n" ); document.write( "(1.85)(1.35)=2.5
\n" ); document.write( "2.5=2.5\r
\n" ); document.write( "
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