document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=926571>Question 926571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Draw an appropriate triangle to find the exact value of :<BR>\n" );
document.write( "1. csc45°<BR>\n" );
document.write( "2. cot30°<BR>\n" );
document.write( "3. sec45°<BR>\n" );
document.write( "4. cot60°<BR>\n" );
document.write( "Can you please help me out and show the steps because it would really help me understand, thank you very much in advance:)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #562356 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=562356\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Draw an appropriate triangle to find the exact value of :<BR>\n" );
document.write( " 1. csc45°<BR>\n" );
document.write( "Draw a 45-45-90 right triangle.<BR>\n" );
document.write( "Let the equal sides be \"1\".<BR>\n" );
document.write( "Then the hypotenuse is sqrt(1^2+1^2) = sqrt(2)<BR>\n" );
document.write( "Then csc(45) = hyp/opp = sqrt(2)/1 = sqrt(2)<BR>\n" );
document.write( "---------------------------------<BR>\n" );
document.write( " 2. cot30°<BR>\n" );
document.write( "Draw a 30-60-90 right triangle.<BR>\n" );
document.write( "Let the side opposite the 30 degree angle be \"1\"<BR>\n" );
document.write( "Then the hypotenuse is \"2\" and the base is sqrt[2^2-1^2] = sqrt(3)<BR>\n" );
document.write( "Then cot(30) adj/opp =  sqrt(3)/1 = sqrt(3)<BR>\n" );
document.write( "--------------------------------<BR>\n" );
document.write( " 3. sec45°<BR>\n" );
document.write( "Use the triangle from #1<BR>\n" );
document.write( "sec(45) = hyp/adj = sqrt(2)/1 = sqrt(2)<BR>\n" );
document.write( "--------------------------<BR>\n" );
document.write( " 4. cot60°<BR>\n" );
document.write( "Use the triangle from #2<BR>\n" );
document.write( "cot(60) = adj/opp = 1/sqrt(3)<BR>\n" );
document.write( "=======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "-----------------------<BR>\n" );
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