document.write( "Question 926473: The length of a rectangle is twice its width.
\n" ); document.write( "If the area of the rectangle is
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Algebra.Com's Answer #562271 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
You are told the that a rectangle has a Length that is twice its Width.\r
\n" ); document.write( "\n" ); document.write( "Let Width = W
\n" ); document.write( "Then Length = 2W\r
\n" ); document.write( "\n" ); document.write( "Area of a rectangle = \"Length+%2A+Width\" = \"2W+%2A+W\" = \"2W%5E2\"
\n" ); document.write( "Perimeter of a rectangle = \"2%2AWidth++=+2%2ALength\" = \"2W+%2B+2%2A2W\" = \"2W+%2B4W\" = \"6W\"\r
\n" ); document.write( "\n" ); document.write( "You are told the area is 128 square feet
\n" ); document.write( "\"128+=+2W%5E2\"
\n" ); document.write( "\"64+=+W%5E2\"
\n" ); document.write( "\"8+=+W\"\r
\n" ); document.write( "\n" ); document.write( "\"Perimeter+=+6W\"\r
\n" ); document.write( "\n" ); document.write( "\"Perimeter+=+6%2A8\"\r
\n" ); document.write( "\n" ); document.write( "\"Perimeter+=+48\"\r
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