document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78294>Question 78294</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 17)	The length of a rectangle is 3 cm more than 2 times its width.  If the area of the rectangle is 99 cm^2, find the dimensions of the rectangle to the nearest thousandth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56222 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56222\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=3+2W<BR>\n" );
document.write( "(3+2W)W=99<BR>\n" );
document.write( "3W+2W^2-99=0<BR>\n" );
document.write( "2W^2+3W-99=0<BR>\n" );
document.write( "USING THE QUADRATIC EQUATION WE GET:<BR>\n" );
document.write( "W=(-3+-SQRT[3^2-4*2*-99])/2*2<BR>\n" );
document.write( "W=(-3+-SQRT[9+792])/4<BR>\n" );
document.write( "W=(-3+-SQRT801)/4<BR>\n" );
document.write( "W=(-3+-28.3)/4<BR>\n" );
document.write( "W=(-3+28.3)/4<BR>\n" );
document.write( "W=25.3/4<BR>\n" );
document.write( "W=6.325 ANSWER.<BR>\n" );
document.write( "L=3+2*6.325<BR>\n" );
document.write( "L=3+12.65 <BR>\n" );
document.write( "L=15.65 ANSWER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "6.325*15.65=99<BR>\n" );
document.write( "99=99<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );