document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=913435>Question 913435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> determine the length of the diagonal of a rectangle with dimensions 3cm x 9cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #562192 by </B><A HREF=/tutors/aboutme.mpl?userid=Roseghanezadeh><B>Roseghanezadeh(16)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Roseghanezadeh><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=562192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So you know the width is 3cm and the length is 9cm. When you draw a diagonal from one corner of the rectangle to its opposite corner, you create a right triangle. To find the length of that diagonal (which is the hypotenuse) you have to use the Pythagorean theorem:<BR>\n" );
document.write( "a^2 + b^2 = c^2<BR>\n" );
document.write( "So now you substitute:<BR>\n" );
document.write( "3^2 + 9^2 = c^2 <BR>\n" );
document.write( "9 + 81= c^2<BR>\n" );
document.write( "c^2 = 90<BR>\n" );
document.write( "c = sqrt(90) <BR>\n" );
document.write( "c = 9.486<BR>\n" );
document.write( "You can also round your answer to:<BR>\n" );
document.write( "c = 9.5cm  </SPAN>\n" );
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