document.write( "Question 78364: Solve each of the following applications. Give all answers to the nearest thousandth. Geometry. The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?
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Algebra.Com's Answer #56218 by checkley75(3666)\"\" \"About 
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this is a right triangle with an hypotenuse of 4 & width of x & the length of (x+1).
\n" ); document.write( "using the pathagorean therum we get
\n" ); document.write( "x^2+(x+1)^2=4^2
\n" ); document.write( "x^2+x^2+2x+1=16
\n" ); document.write( "2x^2+2x+1-16=0
\n" ); document.write( "2x^2+2x-15=0
\n" ); document.write( "using the quadratic equation we get:
\n" ); document.write( "X=(-2+-SQRT[2^2-4*2*-15])/2*2
\n" ); document.write( "X=(-2+-SQRT[4+120])/4
\n" ); document.write( "X=(-2+-SQRT[124])/4
\n" ); document.write( "X=(-2+-11.14)/4
\n" ); document.write( "X=(-2+11.14)/4
\n" ); document.write( "X=9.14/4
\n" ); document.write( "X=2.285 ANSWER.
\n" ); document.write( "X=(-2-1114)/4
\n" ); document.write( "X=-13.14/4
\n" ); document.write( "X=-3.285 ANSWER. \n" ); document.write( "
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