document.write( "Question 926316: A fast cleaner clean 10 rooms in an hour and a slower cleaner 4 rooms in an hour if both work together how long will take to clean 26 rooms \n" ); document.write( "

Algebra.Com's Answer #562159 by ptaylor(2198) $\"\"$ $\"About$

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Let x=time it takes if both working together to clean 26 rooms
\n" ); document.write( "Both working together cleans at the rate of 26/x rooms/hour
\n" ); document.write( "Fast cleaner cleans at the rate of 10 rooms/hour
\n" ); document.write( "Slower cleaner cleans at the rate of 4 rooms/hour
\n" ); document.write( "Our equation to solve then is:
\n" ); document.write( "10+4=(26/x);14=26/x multiply each term by x
\n" ); document.write( "14x=26
\n" ); document.write( "x=26/14=13/7 =1.9 hours
\n" ); document.write( "CHECK
\n" ); document.write( "(I like to deal in fractions rather than decimals; less messy and eliminates round off errors, sooo:)\r
\n" ); document.write( "\n" ); document.write( "In (13/7)) hours, fast cleaner cleans (13/7)*10=130/7 rooms
\n" ); document.write( "In (13/7) hours, slower cleaner cleans (13/7)*4=52/7 rooms
\n" ); document.write( "(130/7)+(52/7) should equal 26
\n" ); document.write( "182/7=26
\n" ); document.write( "26=26\r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( "

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