document.write( "Question 926309: PLEASE HELP ME PLEASE
\n" ); document.write( "IF(4P+1)^2=81 AND P>0,WHAT IA A POSSIBLE VALUE OF P?
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Algebra.Com's Answer #562155 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "if \"%284P%2B1%29%5E2=81\" and \"P%3E0\",...solve for \"P\"\r
\n" ); document.write( "\n" ); document.write( "\"%284P%2B1%29%5E2-81=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%284P%2B1%29%5E2-9%5E2=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28%284P%2B1%29-9%29%28%284P%2B1%29%2B9%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%284P%2B1-9%29%284P%2B1%2B9%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%284P-8%29%284P%2B10%29=0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if \"%284P-8%29=0\" =>\"4P=8\" =>\"P=2\"\r
\n" ); document.write( "\n" ); document.write( "if \"%284P%2B10%29=0\" =>\"4P=-10\" =>\"P=-5%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "since given that \"P%3E0\", we can use only \"P=2\" as a possible value for \"P\"\r
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