document.write( "Question 926183: May is now 3 less than twice as old as Mylene. If the sum of their ages now is 51, find their present ages. \n" ); document.write( "
Algebra.Com's Answer #562108 by Roseghanezadeh(16)\"\" \"About 
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Ok so let May be \"y\" and Mylene be \"x\"
\n" ); document.write( "It says that may is 3 less than twice mylene so:
\n" ); document.write( "y = 2x - 3
\n" ); document.write( "Now it says that the sum of their ages is 51 so:
\n" ); document.write( "x + y = 51\r
\n" ); document.write( "\n" ); document.write( "Now we can substitute \"y\" with \"2x- 3\" in the equation above:
\n" ); document.write( "x + y = 51
\n" ); document.write( "x + 2x - 3 = 51
\n" ); document.write( "Now we have to take like terms to the same side:
\n" ); document.write( "x + 2x = 51 + 3
\n" ); document.write( "3x = 54
\n" ); document.write( "x = 18
\n" ); document.write( "Now we have \"x = 18\" we also knew that \"y = 2x - 3 \"
\n" ); document.write( "So:
\n" ); document.write( "y = 2(18) - 3
\n" ); document.write( "y= 33\r
\n" ); document.write( "\n" ); document.write( "May is 33 years old and Mylene is 18 years old.
\n" ); document.write( "Check:
\n" ); document.write( "x + y = 51
\n" ); document.write( "18 + 33 = 51 \n" ); document.write( "
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