document.write( "Question 926255: the abscissa of a point p is -6 and its distance from the point q(1,3) is √74. find the ordinate of point p \n" ); document.write( "
Algebra.Com's Answer #562094 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! the abscissa of a point p is -6 and its distance from the point q(1,3) is √74. find the ordinate of point p \n" ); document.write( "------ \n" ); document.write( "That is really old terminology. \n" ); document.write( "abscissa is the x-value \n" ); document.write( "ordinate is the corresponding y-value \n" ); document.write( "Your point is (-6,y) \n" ); document.write( "--------------- \n" ); document.write( "Equation: \n" ); document.write( "(y-3)^2 + (-6-1)^2 = 74 \n" ); document.write( "---- \n" ); document.write( "(y-3)^2 + 49 = 74 \n" ); document.write( "----- \n" ); document.write( "(y-3)^2 = 25 \n" ); document.write( "--- \n" ); document.write( "y-3 = 5 or y-3 = -5 \n" ); document.write( "y = 8 or y = -2 \n" ); document.write( "------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------- \n" ); document.write( " |