document.write( "Question 926255: the abscissa of a point p is -6 and its distance from the point q(1,3) is √74. find the ordinate of point p \n" ); document.write( "
Algebra.Com's Answer #562094 by stanbon(75887)\"\" \"About 
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the abscissa of a point p is -6 and its distance from the point q(1,3) is √74. find the ordinate of point p
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\n" ); document.write( "That is really old terminology.
\n" ); document.write( "abscissa is the x-value
\n" ); document.write( "ordinate is the corresponding y-value
\n" ); document.write( "Your point is (-6,y)
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\n" ); document.write( "Equation:
\n" ); document.write( "(y-3)^2 + (-6-1)^2 = 74
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\n" ); document.write( "(y-3)^2 + 49 = 74
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\n" ); document.write( "(y-3)^2 = 25
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\n" ); document.write( "y-3 = 5 or y-3 = -5
\n" ); document.write( "y = 8 or y = -2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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