document.write( "Question 925880: The width of a rectangle is one more than half its length. If the length is tripled and the width left unchanged, the new perimeter would be 58 cm. what is the area of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #562088 by lwsshak3(11628)\"\" \"About 
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The width of a rectangle is one more than half its length. If the length is tripled and the width left unchanged, the new perimeter would be 58 cm. what is the area of the original rectangle?
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\n" ); document.write( "original rectangle:
\n" ); document.write( "let x=length
\n" ); document.write( "1+x/2=width
\n" ); document.write( "new rectangle:
\n" ); document.write( "3x=length
\n" ); document.write( "1+x/2=(2+x)/2
\n" ); document.write( "perimeter=2*length+2*width
\n" ); document.write( "6x+2+x=58
\n" ); document.write( "7x=56
\n" ); document.write( "x=8
\n" ); document.write( "..
\n" ); document.write( "area of original rectangle=x(1+x/2)=8(1+4)=8*5=40 cm^2
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