document.write( "Question 926215: A plane travels 1050 miles with a tail wind in 2 hours and 30 minutes and returns in 3 houts and 30 minutes against the head wind. Find the speed of the plane in still air and the wind velocity. \n" ); document.write( "
Algebra.Com's Answer #562085 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! A plane travels 1050 miles with a tail wind in 2 hours and 30 minutes and returns in 3 hours and 30 minutes against the head wind. Find the speed of the plane in still air and the wind velocity. \n" ); document.write( "*** \n" ); document.write( "let x=speed of plane in stll air \n" ); document.write( "let c=speed of wind \n" ); document.write( "x+c=speed of plane with tail wind \n" ); document.write( "x-c=speed of plane with head wind \n" ); document.write( "travel time=distance/speed \n" ); document.write( ".. \n" ); document.write( "1050/(x+c)=2.5 \n" ); document.write( "1050/(x-c)=3.5 \n" ); document.write( ".. \n" ); document.write( "2.5x+2.5c=1050 \n" ); document.write( "3.5x-3.5c=1050 \n" ); document.write( ".. \n" ); document.write( "8.75x+8.75c=3675 (mult eq. by 3.5) \n" ); document.write( "8.75x-8.75c=2625 (mult eq. by 2.5) \n" ); document.write( "add \n" ); document.write( "17.5x=6300 \n" ); document.write( "x=360 \n" ); document.write( "2.5c=1050-2.5x=1050-900=150 \n" ); document.write( "c=60 \n" ); document.write( "speed of plane in stll air=360 mph \n" ); document.write( "speed of wind=60 mph \n" ); document.write( " \n" ); document.write( " |