document.write( "Question 926144: At a certain university the cumulative grade point average (CGPA) of first year students usually averages 2.48 with a standard deviation 0.42 . It has been found that the marks are usually approximately normally distributed.
\n" ); document.write( "a) What is the probability that a student will have a CGPA that is between 1 and 3 ? \r
\n" ); document.write( "\n" ); document.write( "b) What percent of students will be on probation, i.e. their CGPA is less than 2 ? \r
\n" ); document.write( "\n" ); document.write( "c) Academic scholarships are awarded to the top 5% of first year students. What minimum CGPA is needed to receive a scholarship?
\n" ); document.write( "

Algebra.Com's Answer #562055 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
At a certain university the cumulative grade point average (CGPA) of first year students usually averages 2.48 with a standard deviation 0.42 . It has been found that the marks are usually approximately normally distributed.
\n" ); document.write( "a) What is the probability that a student will have a CGPA that is between 1 and 3 ?
\n" ); document.write( "z(1) = (1-2.48)/0.42 = -3.5238
\n" ); document.write( "z(3) = (3-2.48)/0.42 = 1.2381
\n" ); document.write( "----
\n" ); document.write( "P(1< x < 3) = P(-3.5238 < z < 1.2381) = normalcdf(-3.5338,1.2381) = 0.8920
\n" ); document.write( "----------------------
\n" ); document.write( " b) What percent of students will be on probation, i.e. their CGPA is less than 2 ?
\n" ); document.write( "z(2) = (2-2.48)/0.42 = -1.1429
\n" ); document.write( "P(x < 2) = P(z < -1.1429) = normalcdf(-100,-1.1429) = 0.1265
\n" ); document.write( "-----------------------
\n" ); document.write( " c) Academic scholarships are awarded to the top 5% of first year students. What minimum CGPA is needed to receive a scholarship?
\n" ); document.write( "Find the z-value with a right-tail of 0.05
\n" ); document.write( "invnorm(0.95) = 1.645
\n" ); document.write( "Find the corresponding score::
\n" ); document.write( "x = 1.645*0.42 + 2.48 = 3.1708
\n" ); document.write( "--------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "---------------------
\n" ); document.write( "
\n" );