document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=926120>Question 926120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you please show me the workings for the following equation please<BR>\n" );
document.write( "3y+16=6y-1  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #562009 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=562009\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ok<BR>\n" );
document.write( "3y+16=6y-1 <BR>\n" );
document.write( "First lets collect like terms (get the y's on one side and the numbers on the other)<BR>\n" );
document.write( "We can do this by subtracting 16 from each side and also 6y from each side:\r<BR>\n" );
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document.write( "Here's what it looks like<BR>\n" );
document.write( "3y+16-16-6y=6y-6y-16-1----  16-16=0 and 6y-6y=0 and here's what we are left with:<BR>\n" );
document.write( "3y-6y=-16-1<BR>\n" );
document.write( "-3y=-17<BR>\n" );
document.write( "y=-17/-3=17/3 we can leave it like this or divide it out<BR>\n" );
document.write( "CHECK<BR>\n" );
document.write( "3*(17/3)+16=6*(17/3)-1<BR>\n" );
document.write( "17+16=34-1<BR>\n" );
document.write( "33=33\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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