document.write( "Question 926120: Could you please show me the workings for the following equation please
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document.write( "3y+16=6y-1 \n" );
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Algebra.Com's Answer #562004 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 3y+16=6y-1 \n" ); document.write( "---- \n" ); document.write( "Subtract 3y from both sides to get: \n" ); document.write( "16 = 3y-1 \n" ); document.write( "--- \n" ); document.write( "Add \"1\" to both sides to get: \n" ); document.write( "3y = 17 \n" ); document.write( "---- \n" ); document.write( "Divide both sides by 3 to get:: \n" ); document.write( "y = 17/3 = 5 2/3 \n" ); document.write( "----------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------------- \n" ); document.write( " \n" ); document.write( " |